Optimal. Leaf size=440 \[ -\frac{\left (-\sqrt{b^2-4 a c}+b+2 c x\right ) (d+e x)^{m+3} \left (a+b x+c x^2\right )^{-\frac{m}{2}-2} \left (4 c e (a e-b d (m+1))+b^2 e^2 m+4 c^2 d^2 (m+1)\right ) \left (\frac{\left (\sqrt{b^2-4 a c}+b+2 c x\right ) \left (2 c d-e \left (b-\sqrt{b^2-4 a c}\right )\right )}{\left (-\sqrt{b^2-4 a c}+b+2 c x\right ) \left (2 c d-e \left (\sqrt{b^2-4 a c}+b\right )\right )}\right )^{\frac{m+4}{2}} \, _2F_1\left (m+3,\frac{m+4}{2};m+4;-\frac{4 c \sqrt{b^2-4 a c} (d+e x)}{\left (2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e\right ) \left (b+2 c x-\sqrt{b^2-4 a c}\right )}\right )}{4 (m+1) (m+3) \left (2 c d-e \left (b-\sqrt{b^2-4 a c}\right )\right ) \left (a e^2-b d e+c d^2\right )^2}+\frac{e (d+e x)^{m+1} \left (a+b x+c x^2\right )^{-\frac{m}{2}-1}}{(m+1) \left (a e^2-b d e+c d^2\right )}+\frac{e m (2 c d-b e) (d+e x)^{m+2} \left (a+b x+c x^2\right )^{-\frac{m}{2}-1}}{2 (m+1) (m+2) \left (a e^2-b d e+c d^2\right )^2} \]
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Rubi [A] time = 0.385077, antiderivative size = 440, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.115, Rules used = {744, 806, 726} \[ -\frac{\left (-\sqrt{b^2-4 a c}+b+2 c x\right ) (d+e x)^{m+3} \left (a+b x+c x^2\right )^{-\frac{m}{2}-2} \left (4 c e (a e-b d (m+1))+b^2 e^2 m+4 c^2 d^2 (m+1)\right ) \left (\frac{\left (\sqrt{b^2-4 a c}+b+2 c x\right ) \left (2 c d-e \left (b-\sqrt{b^2-4 a c}\right )\right )}{\left (-\sqrt{b^2-4 a c}+b+2 c x\right ) \left (2 c d-e \left (\sqrt{b^2-4 a c}+b\right )\right )}\right )^{\frac{m+4}{2}} \, _2F_1\left (m+3,\frac{m+4}{2};m+4;-\frac{4 c \sqrt{b^2-4 a c} (d+e x)}{\left (2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e\right ) \left (b+2 c x-\sqrt{b^2-4 a c}\right )}\right )}{4 (m+1) (m+3) \left (2 c d-e \left (b-\sqrt{b^2-4 a c}\right )\right ) \left (a e^2-b d e+c d^2\right )^2}+\frac{e (d+e x)^{m+1} \left (a+b x+c x^2\right )^{-\frac{m}{2}-1}}{(m+1) \left (a e^2-b d e+c d^2\right )}+\frac{e m (2 c d-b e) (d+e x)^{m+2} \left (a+b x+c x^2\right )^{-\frac{m}{2}-1}}{2 (m+1) (m+2) \left (a e^2-b d e+c d^2\right )^2} \]
Antiderivative was successfully verified.
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Rule 744
Rule 806
Rule 726
Rubi steps
\begin{align*} \int (d+e x)^m \left (a+b x+c x^2\right )^{-2-\frac{m}{2}} \, dx &=\frac{e (d+e x)^{1+m} \left (a+b x+c x^2\right )^{-1-\frac{m}{2}}}{\left (c d^2-b d e+a e^2\right ) (1+m)}+\frac{\int (d+e x)^{1+m} \left (\frac{1}{2} (-b e m+2 c d (1+m))+c e x\right ) \left (a+b x+c x^2\right )^{-2-\frac{m}{2}} \, dx}{\left (c d^2-b d e+a e^2\right ) (1+m)}\\ &=\frac{e (d+e x)^{1+m} \left (a+b x+c x^2\right )^{-1-\frac{m}{2}}}{\left (c d^2-b d e+a e^2\right ) (1+m)}+\frac{e (2 c d-b e) m (d+e x)^{2+m} \left (a+b x+c x^2\right )^{-1-\frac{m}{2}}}{2 \left (c d^2-b d e+a e^2\right )^2 (1+m) (2+m)}+\frac{\left (b^2 e^2 m+4 c^2 d^2 (1+m)+4 c e (a e-b d (1+m))\right ) \int (d+e x)^{2+m} \left (a+b x+c x^2\right )^{-2-\frac{m}{2}} \, dx}{4 \left (c d^2-b d e+a e^2\right )^2 (1+m)}\\ &=\frac{e (d+e x)^{1+m} \left (a+b x+c x^2\right )^{-1-\frac{m}{2}}}{\left (c d^2-b d e+a e^2\right ) (1+m)}+\frac{e (2 c d-b e) m (d+e x)^{2+m} \left (a+b x+c x^2\right )^{-1-\frac{m}{2}}}{2 \left (c d^2-b d e+a e^2\right )^2 (1+m) (2+m)}-\frac{\left (b^2 e^2 m+4 c^2 d^2 (1+m)+4 c e (a e-b d (1+m))\right ) \left (b-\sqrt{b^2-4 a c}+2 c x\right ) \left (\frac{\left (2 c d-\left (b-\sqrt{b^2-4 a c}\right ) e\right ) \left (b+\sqrt{b^2-4 a c}+2 c x\right )}{\left (2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e\right ) \left (b-\sqrt{b^2-4 a c}+2 c x\right )}\right )^{\frac{4+m}{2}} (d+e x)^{3+m} \left (a+b x+c x^2\right )^{-2-\frac{m}{2}} \, _2F_1\left (3+m,\frac{4+m}{2};4+m;-\frac{4 c \sqrt{b^2-4 a c} (d+e x)}{\left (2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e\right ) \left (b-\sqrt{b^2-4 a c}+2 c x\right )}\right )}{4 \left (2 c d-\left (b-\sqrt{b^2-4 a c}\right ) e\right ) \left (c d^2-b d e+a e^2\right )^2 (1+m) (3+m)}\\ \end{align*}
Mathematica [A] time = 3.78267, size = 379, normalized size = 0.86 \[ \frac{(d+e x)^{m+1} (a+x (b+c x))^{-\frac{m}{2}-2} \left (\frac{(d+e x)^2 \left (\sqrt{b^2-4 a c}+b+2 c x\right ) \left (-4 c e (b d (m+1)-a e)+b^2 e^2 m+4 c^2 d^2 (m+1)\right ) \left (\frac{\left (\sqrt{b^2-4 a c}+b+2 c x\right ) \left (e \left (\sqrt{b^2-4 a c}-b\right )+2 c d\right )}{\left (\sqrt{b^2-4 a c}-b-2 c x\right ) \left (e \left (\sqrt{b^2-4 a c}+b\right )-2 c d\right )}\right )^{\frac{m+2}{2}} \, _2F_1\left (m+3,\frac{m+4}{2};m+4;-\frac{4 c \sqrt{b^2-4 a c} (d+e x)}{\left (\left (b+\sqrt{b^2-4 a c}\right ) e-2 c d\right ) \left (-b-2 c x+\sqrt{b^2-4 a c}\right )}\right )}{2 (m+3) \left (e \left (\sqrt{b^2-4 a c}+b\right )-2 c d\right )}+2 e (a+x (b+c x)) \left (e (a e-b d)+c d^2\right )+\frac{e m (d+e x) (a+x (b+c x)) (2 c d-b e)}{m+2}\right )}{2 (m+1) \left (e (a e-b d)+c d^2\right )^2} \]
Antiderivative was successfully verified.
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Maple [F] time = 1.258, size = 0, normalized size = 0. \begin{align*} \int \left ( ex+d \right ) ^{m} \left ( c{x}^{2}+bx+a \right ) ^{-2-{\frac{m}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (c x^{2} + b x + a\right )}^{-\frac{1}{2} \, m - 2}{\left (e x + d\right )}^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (c x^{2} + b x + a\right )}^{-\frac{1}{2} \, m - 2}{\left (e x + d\right )}^{m}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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